From 2-b, consider a new vector field A'(x) = \mu_0 / 4 \pi \int j(y) / |x| d^3 y.
if you accept these definition, then we can write that A(x) = A'(x-y).
using this, you can make a Taylor expansion of A(x) = A'(x-y).
PS. there was a homework problem using exactly the same method to this.
go back to HW #3 problem 5-b.
i think you must learn some lesson from this.
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